Hi guys, Working on a 50-ton hydraulic press design using a standard H-frame design, like this: I'm working on the design of the vertical members. Similar to the photo above, the verticals have 1.25" diameter holes drilled for pins that support the horizontal bed. The problem: while determining the size of steel to use, I'm finding that the hole stresses require a much thicker steel than what I see being used in commercial machines. Specifically, in order to support the maximum 50-ton load, that equates to 25,000 lbf per vertical support. If I use two 1.25" pins per side (4 total) to support the horizontal bed, that works out to 12,500 lbf of force per hole. I've modeled a 1"x4" A36 flat bar at some length with 1.25" dia. holes space 5" apart. The base is fixed, there is a bearing force of 12,500 lbf per hole (so 25,000 lbf total), and a reaction force of 25,000 lbf along the top of the bar. Running SolidWorks Simulation, I get the following: The max stress is in the top hole, 27,600 psi. While this is OK, if I use, say, 1/2" plate, it yields. Commercial units I've seen use 1/2" or less. Many only use a single pin per side. I just don't get it. Am I doing something wrong here? Are the manufactures not taking into account the hole stresses? Are they not as important as I'm suspecting? Any feedback would be greatly appreciated. Thank you!