The load bearing piston in a hydraulic system as an area 50 times as the the input piston. If the larger piston supports a load of 6000N, how large a force must be applied to the input piston?(adsbygoogle = window.adsbygoogle || []).push({});

Since the area is 50 times as large i used a ratio 10:50

Using the formula F2/F1 = A2/A1

6000/F1 = 50/10

6000/F1 = 5

F1 = 6000/5

= 1200N

I have no idea if i am anywhere close!!!!!

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# Homework Help: Hydraulic question

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