- #1
Allday
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The hydrogen energy levels (when only considering the coulomb field of an infinitely massive proton - or when using the reduced mass for the electron) only depend on the principle quantum number n. Can someone give me a qualitative argument why the orbital angular momentum quantum number l doesn't come into play here?
related questions:
do hydrogen like atoms (ionized to the point of having only one electron but containing more than one proton) break this degeneracy between the different orbital angular momentum states?
do atoms with the same number of protons and electrons, but with one electron outside of completely full shells break this degeneracy?
gonna read some and see if i can find the answer
related questions:
do hydrogen like atoms (ionized to the point of having only one electron but containing more than one proton) break this degeneracy between the different orbital angular momentum states?
do atoms with the same number of protons and electrons, but with one electron outside of completely full shells break this degeneracy?
gonna read some and see if i can find the answer
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