hi. i think that hydrogen economy is possible. see this maths ther is gonna be a cylinder with a volume of exactly 1 litre. hydrogen and oxygen are introduced in the volume ratio of 2:1. volume of cylinder = 1000cm3 volume of hydrogen = 666.6666......cm3 volume of oxygen = 333.3333...cm3 mass of hydrogen = 0.08988(density in g/L) * 0.666(mass in grams) = 0.0598g mass of oxygen = 1.429(density in g/L) * 0.333(mass in grams) = 0.475g energy liberated = 0.0598(mass) * 142800(calorific value converted into joules) = 8359.44J = 8.35944kJ mass of water vapour generated after the combustion will be equal to the mass of oxygen + mass of oxygen. mass of water vapour = 0.5348g = 0.0005348Kg specific heat of water vapour = 1.864kJ/KgK heat attained(in K) = heat evolved/(mass * specific heat capacity) = 8.35944/(0.0005348 * 1.864) = 29136 kelvin that is an incredible amount of heat. are my calculations right? if no please tell where the mistake is. anyone can ask clarifications. iam dead serious about this. please help me and help yourself. help mother earth.