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Hydrogen radial equation solution

  1. Apr 20, 2017 #1
    I am going through my Quantum textbook, just reviewing the material, i.e. this isn't a homework question. We are solving the radial equation for the Hydrogen Atom, first looking at the asymptotic behavior. My issue is I am completely blanking on how to solve the differential equation:

    d^2u/dp^2 = [l(l+1)/p^2]u.

    The general solution is:

    u(p) = Cp^(l+1) + Dp^-l.

    Can someone walk me through the steps of getting to this general solution? Thank you!
     
  2. jcsd
  3. Apr 20, 2017 #2

    stevendaryl

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    With differential equations, solving them often just means guessing a solution, and then tweaking parameters to get the equations to work out.

    You have the equation: [itex]\frac{d^2 u}{dp^2} = \frac{\mathcal{l}(\mathcal{l}+1)}{p^2} u[/itex].
    You guess: [itex]u = p^\alpha[/itex].

    Then [itex]\frac{du}{dp} = \alpha p^{\alpha-1}[/itex] and [itex]\frac{d^2 u}{dp^2} = \alpha (\alpha -1) p^{\alpha - 2}[/itex]. Plugging this into the differential equation gives:

    [itex]\alpha (\alpha - 1) p^{\alpha - 2} = \frac{\mathcal{l}(\mathcal{l} + 1)}{p^2} p^\alpha[/itex]

    For the equation to be true, [itex]\alpha (\alpha - 1) = \mathcal{l} (\mathcal{l} + 1)[/itex]

    So two possibilities are: [itex]\alpha = -\mathcal{l}[/itex] and [itex]\alpha = \mathcal{l} + 1[/itex]

    The general solution is a linear combination of the solutions.
     
  4. Apr 20, 2017 #3
    Ok, thank you so much!
     
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