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Hydronium treatment

  1. Dec 4, 2013 #1
    Is it true that the reaction 2 H2O = H3O+ + OH- has a different equilibrium constant to that of Kw, H2O = H+ + OH- ? How can that be?

    If we want a decent treatment of an acid-base system using [H3O+] rather than the less accurate [H+], what modifications do we have to make to the process used for the simple [H+] case?
  2. jcsd
  3. Dec 4, 2013 #2
    No modifications necessary, they are treated exactly the same. It's simply a matter of changing the labels because free protons are not thought to exist in solution such that it is more realistic to denote the proton by using the hydronium label.
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