- #1

SPhy

- 25

- 0

## Homework Statement

"Set up the integral to find the hydrostatic force on the face of the aquarium water tank, whose cross sectional area can be described by, y = e^

^{-x^2}on 0.5≤x≤4.5 meters, resting at the bottom of the water 4 meters deep. Assume the bound y=0".

## The Attempt at a Solution

Using the formula

F = bounds[0,a] ∫ρg(a-y)(w(y))dy , essentially, depth x width x gravity x water density

To find width, write y= e^

^{-x^2}in terms of x, yields, x=√ln(1/y) consider only positive values.

integral so far,

F= bounds[0,a] ∫pg(a-y)√ln(1/y) dy

My issue is finding a. Since the book gives the condition y=0, I assume the height of the water = height of tank, so can I say a=4?

Hopefully that made sense. In many problems done so far that are similar to this one, im finding the force on a window, so my A value on the integral bound is different from my A value in the depth expression. I might be thinking about this problem completely backwards, so any help or suggestions would be welcomed!