I need help proving this hyperbolic function(adsbygoogle = window.adsbygoogle || []).push({});

Prove that

[tex]\tan^{-1}\hbar {x}=\frac{1}{2}\ln\frac{1+x}{1-x}[/tex]

my work

x=e^y-e^-y/e^y+e^-y

(e^y+e^-y)x=e^y-e^-y

0=e^y-e^-y-xe^y+xe^-y

e^y(e^y-e^-y-xe^y+xe^-y)

e^2y-x(e^2y)-1+x=0

I know i have to use the quadratic equation here

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# Hyperbolic function proof

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