- #1

- 59

- 0

## Homework Statement

If sinhx=tany show x=ln(tany±secy)

## Homework Equations

sinhx=0.5(e^x-e^(-x))

secy=1/cosy

cosy=0.5(e^y+e^(-y))

tany=(e^(jx)-e^(-jx))/(e^(jx)+e^(-jx))

tany=siny/cosy

## The Attempt at a Solution

0.5e^x -0.5e^-x=tany

0.5e^(2x) -0.5=tany e^x

e^(2x) -2tany e^x -1 = 0

e^(2x) = (2tany±square[(-2tany)^2 + 4] / 2

Is this good so far, and what to do with 4tan^2y?