- #1
Pietair
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Homework Statement
If sinhx=tany show x=ln(tany±secy)
Homework Equations
sinhx=0.5(e^x-e^(-x))
secy=1/cosy
cosy=0.5(e^y+e^(-y))
tany=(e^(jx)-e^(-jx))/(e^(jx)+e^(-jx))
tany=siny/cosy
The Attempt at a Solution
0.5e^x -0.5e^-x=tany
0.5e^(2x) -0.5=tany e^x
e^(2x) -2tany e^x -1 = 0
e^(2x) = (2tany±square[(-2tany)^2 + 4] / 2
Is this good so far, and what to do with 4tan^2y?