- #1

- 241

- 0

y=km(ln(cosh(gt/km)^(1/2)))

constants k and m

dy/dx=gtanh((gt/km)^(1/2))/(2(gt/km)^(1/2))...?

constants k and m

dy/dx=gtanh((gt/km)^(1/2))/(2(gt/km)^(1/2))...?

- Thread starter nameVoid
- Start date

- #1

- 241

- 0

y=km(ln(cosh(gt/km)^(1/2)))

constants k and m

dy/dx=gtanh((gt/km)^(1/2))/(2(gt/km)^(1/2))...?

constants k and m

dy/dx=gtanh((gt/km)^(1/2))/(2(gt/km)^(1/2))...?

- #2

Mark44

Mentor

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Is it

a)[tex]y = km~ln(\sqrt{cosh(gt/(km))}~)[/tex]

or

b)[tex]y = km~ln(cosh(\sqrt{gt/(km)}~))[/tex]

?

As you wrote the problem, it would be a, but your derivative (which should be dy/dt) suggests it is b.

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