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Hyperbolic functions

  1. Sep 29, 2009 #1
    y=km(ln(cosh(gt/km)^(1/2)))
    constants k and m
    dy/dx=gtanh((gt/km)^(1/2))/(2(gt/km)^(1/2))...?
     
  2. jcsd
  3. Sep 29, 2009 #2

    Mark44

    Staff: Mentor

    Don't think so, but I'm not sure how the problem is actually stated.

    Is it
    a)[tex]y = km~ln(\sqrt{cosh(gt/(km))}~)[/tex]

    or
    b)[tex]y = km~ln(cosh(\sqrt{gt/(km)}~))[/tex]
    ?
    As you wrote the problem, it would be a, but your derivative (which should be dy/dt) suggests it is b.
     
  4. Sep 29, 2009 #3
    b sorry my mistake im working on the second derivative now it seems a bit to messy but I dont see an error in y'
     
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