Hyperbolic functions

  • Thread starter nameVoid
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  • #1
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y=km(ln(cosh(gt/km)^(1/2)))
constants k and m
dy/dx=gtanh((gt/km)^(1/2))/(2(gt/km)^(1/2))...?
 

Answers and Replies

  • #2
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Don't think so, but I'm not sure how the problem is actually stated.

Is it
a)[tex]y = km~ln(\sqrt{cosh(gt/(km))}~)[/tex]

or
b)[tex]y = km~ln(cosh(\sqrt{gt/(km)}~))[/tex]
?
As you wrote the problem, it would be a, but your derivative (which should be dy/dt) suggests it is b.
 
  • #3
241
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b sorry my mistake im working on the second derivative now it seems a bit to messy but I dont see an error in y'
 

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