1. Sep 29, 2009 #1

   nameVoid

   

   y=km(ln(cosh(gt/km)^(1/2)))
   constants k and m
   dy/dx=gtanh((gt/km)^(1/2))/(2(gt/km)^(1/2))...?

    

   nameVoid, Sep 29, 2009
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3. Sep 29, 2009 #2

   Mark44

   

   Insights Author

   Staff: Mentor

   Don't think so, but I'm not sure how the problem is actually stated.
   
   Is it
   a)[tex]y = km~ln(\sqrt{cosh(gt/(km))}~)[/tex]
   
   or
   b)[tex]y = km~ln(cosh(\sqrt{gt/(km)}~))[/tex]
   ?
   As you wrote the problem, it would be a, but your derivative (which should be dy/dt) suggests it is b.

    

   Mark44, Sep 29, 2009
4. Sep 29, 2009 #3

   nameVoid

   

   b sorry my mistake im working on the second derivative now it seems a bit to messy but I dont see an error in y'

    

   nameVoid, Sep 29, 2009

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