- #1
bard
- 65
- 0
at what point on the curve [tex]y=\cosh x[/tex] does the tangent have slope 1
I have no idea how to approach this problem
my work
[tex]1=\sinh x\frac{dy}{dx}[/tex]
[tex]\frac{1}{sinh x}=\frac{dy}{dx}[/tex]
I have no idea how to approach this problem
my work
[tex]1=\sinh x\frac{dy}{dx}[/tex]
[tex]\frac{1}{sinh x}=\frac{dy}{dx}[/tex]