I am having trouble with a problem that asks me to show that if I change the variable of integration of the following equation from t to t-1 the following [Broken] (disregard that z in the denominator, that should not be there) will equal the following [Broken] (this one uses z's instead of t's) I have tried simply changing the all the t's to t-1, and the only differentiating the t-1 term. That of course didn't work. I also tried a U substitution and that gave me an integral that looked like it couldn't be solved analytically (if you want me to post that code I can). I am not sure whether I even need to integrate, or whether this is one of those problems with a really quick shortuct and I can avoid doing any integration. Anyways, any help would be appreicated, thanks.