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How would i go about showing the special case F(1, b, b; x) of the hypergeometic function is the geometric series and also how the geometric series is = 1/ (1 -x)
Cheers,
Dave
Cheers,
Dave
The geometric series ?? I get the series of [itex] e^{x} [/itex].
Daniel.
Cheers thanksOk, my mistake. The factorial in the denominator simplifies through. So
[tex] _{2}F_{1}\left(1,b;b;x\right)=\sum_{\nu=0}^{\infty} x^{\nu} [/tex]
which converges for |x|<1 to [itex] \frac{1}{1-x} [/itex]
Daniel.