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Homework Help: I am Needing help with Moles

  1. Feb 23, 2007 #1
    1. :confused: :confused: :confused:

    i tried some of them but i am not sure if they are right.
    What is the mass of one mole of aluminum?


    I don't understand how to do this and


    What is the mass of one mole of hydrogen?

    1.008 g
    2.040g
    3.000 g
    1008 g



    What is the mass of one mole of carbon dioxide, CO2?

    3.4007 x 102 g
    2.2 x 102 g
    4.4009 x 101 g
    22.09 x 102 g


    What is the mass of one mole of sulfuric acid?

    9.8079 x 101 g
    98.079 x 103 g
    980.79 x 105 g
    98079 x 101 g


    How many moles in 3.00 g H2SO4?

    .059 mol
    .390 mol
    4.03 mol
    .030 mol




    How many moles in 12.0 g CH4?

    .748 mol
    22.5 mol
    .495 mol
    .952 mol




    How many moles in 3.40 x 101g CaO?

    .0900 mol
    .0456 mol
    .945 mol
    .606 mol




    How many moles in 13.4 g SO2?

    .45 mol
    .21mol
    .97 mol
    .25 mol




    What is the mass of 0.369 mol N2?

    10.337 g
    14.986 g
    12.031 g
    15.0987 g




    What is the mass of 10.0 mol Ca(NO3)2?

    1596 g
    12906g
    1641 g
    1498 g


    What is the mass of 1.94 x 10-3 mol C6H12O6?

    .340 g
    .456 g
    .905 g
    22.5 g


    What is the mass of 0.0112 KCl ?

    5.956 g


    How many particles in 25.9 mol Fe ?

    1.56 x 1014


    How many particles in 0.30 mol NaCl ?

    1.8 x 1034

    How many moles in 4.7 x 1024 atoms Cu?

    7.8

    How many moles in 8.30 x 1025 molecules H2O?


    156
     
  2. jcsd
  3. Feb 23, 2007 #2
    For the first few questions n=M/m is your equation.
    n= # of moles
    M= mass in Kg
    m= molecular mass (sum of neutrons and protons)

    Not to sure about the molecule and particle questions.
    I'm pretty sure there is 6.02*10^23 atoms in 1 mole.
     
  4. Feb 23, 2007 #3
    This is solved by units where moles=g/g/mole and moles equals atoms/atoms/mole, these two should help solve for exchanges to mass and number of atoms.
     
  5. Feb 23, 2007 #4
    thanks:) I will try it and see if it helps you guys:)
     
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