1. Given y= (2e^t + 3e^-t ) / (e^t + 2e^-t)(adsbygoogle = window.adsbygoogle || []).push({});

find inverse of of the equation from above

i did the working out to get

y= ([2t-3] / [2-t]) ^ 1/2

do i have to apply any log laws or anything like that?

2. cosh x = 4.5 find sinh x exactly

i applied the formula

(coshx)^2 - (sinhx)^2 = 1

therefore

- (sinhx)^2 = 1 - (coshx)^2

(sinhx)^2 = -1 + (4.5)^2

(sinhx)^2 = 19.25

sinhx = sqrt 19.25

is that exactly????

3. express as partial fractions

(10x^2 + 14x + 3) / (x^3 + 3x^2 - 4)

i got

[7/(x+2)] - [5/(x+2)^2] + [3/(x-1)]

is that right?

PLEASE REPLY THANKS

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# Homework Help: I Find This Very Hard Can Somebody Check This Out

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