# I found a lepton mass ratio formula:

1. Jul 25, 2004

### Hans de Vries

I found the following (for what it’s worth):

ln(mu/me) / (2pi-3/pi) = 1.000627
ln(mt/me) / (3pi-4/pi) = 1.00031

me = 0.51099892 MeV (+/-0.00000004)
mu = 105.658369 MeV (+/-0.000009)
mt = 1776.99000 MeV (+0.29 -0.26)

I've not seen it before. There's no theory behind it.
I was trying one, made a bug and stumbled on it.

Regards, Hans

2. Jul 25, 2004

### urtalkinstupid

Nice. I'm really in to Leptons. I like this post.

What exactly do you mean by me, mu, and mt?

Do you mean $\nu_e$, $\nu_\mu$, and $\nu_\tau$ for electron neutrino, muon neutrino, and tau neutrino respectively?

3. Jul 25, 2004

### Hans de Vries

It relates the masses of the electron, the muon and the tau lepton.

ln(mu/me) is the natural logarithm of the ratio between the muon mass
and the electron mass. The value 2pi-3/pi describes it with an accuracy
of 0.06% The other one is twice as exact.

Regards, Hans de Vries

4. Jul 25, 2004

### urtalkinstupid

Anything with neutrinos and their mass ratios?

5. Jul 26, 2004

### Hans de Vries

Unfortunately. there's not enough know about the neutriono masses.
For decades (until recently) it was believed that they had no mass at all.
This is what is known about the upper mass limits:

ve Mass < 3 eV
vu mass < 0.19 MeV
vt mass < 18.2 MeV

Regards, Hans

6. Jul 27, 2004

### Hans de Vries

There's more here:

http://www.chip-architect.com/news/2004_07_27_The_Electron.html [Broken]

Regards, Hans

Last edited by a moderator: May 1, 2017
7. Aug 3, 2004

### arivero

it is really intriguing.
I wonder if it applies to quarks to, perhaps changing -1/pi -> +1/pi, or directly.

8. Aug 3, 2004

### Chronos

For even more fun, try adding up the quark mass and see if it equals the proton mass.

9. Aug 3, 2004

### arivero

Chronos, for sure it does not. You must account also the energy of force carriers, which form a glueball.