- #1

wachaif

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Response to:

force question

i dont understand this..the way the forces go

if someone could show me how to do it and the steps..that would be great:

The static friction coefficient btw a wall and a pic is 0.7 while the kinetic one is 0.3. By what force shoudl one push the 6kg pic against the wall so that it will not slide?What if he/she pushed the pic with a force making an angle of 30 degrees to the horizontal (both cases)

1. Break the F into x-y component such as x=Fcos30 ,y = Fsin30

2.Since friction= U times normal force .and the normal force =Fcos 30

3.Set f=mg+Fsin30

U(Fcos30)=6(9.8) + F sin 30

0.7(Fcos30)=6(9.8) + F sin 30

F=553.58N

Am I correct ?

force question

i dont understand this..the way the forces go

if someone could show me how to do it and the steps..that would be great:

The static friction coefficient btw a wall and a pic is 0.7 while the kinetic one is 0.3. By what force shoudl one push the 6kg pic against the wall so that it will not slide?What if he/she pushed the pic with a force making an angle of 30 degrees to the horizontal (both cases)

1. Break the F into x-y component such as x=Fcos30 ,y = Fsin30

2.Since friction= U times normal force .and the normal force =Fcos 30

3.Set f=mg+Fsin30

U(Fcos30)=6(9.8) + F sin 30

0.7(Fcos30)=6(9.8) + F sin 30

F=553.58N

Am I correct ?

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