- #1
ZedCar
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Have I done this correctly? Thank you.
A particle of mass 2kg moves under the action of forces 3i - 12j, and i + 6j.
(i) Find the resultant force acting on the particle in the form ai + bj
(ii) Find the acceleration of the particle
F = ma
(i)
R = 3i + i - 12j + 6j
R = 4i - 6j
(ii)
Using F = ma
4i - 6j = 2a
2i - 3j = a
asquared = 2squared + (-3)squared
a = square root of (4 + 9)
a = square root of 13
Homework Statement
A particle of mass 2kg moves under the action of forces 3i - 12j, and i + 6j.
(i) Find the resultant force acting on the particle in the form ai + bj
(ii) Find the acceleration of the particle
Homework Equations
F = ma
The Attempt at a Solution
(i)
R = 3i + i - 12j + 6j
R = 4i - 6j
(ii)
Using F = ma
4i - 6j = 2a
2i - 3j = a
asquared = 2squared + (-3)squared
a = square root of (4 + 9)
a = square root of 13