1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

I just need someone to check my work please: glass ornament

  1. Mar 30, 2007 #1
    1. The problem statement, all variables and given/known data
    [​IMG]
    thank you!!!!!

    2. Relevant equations



    3. The attempt at a solution
    1. The problem statement, all variables and given/known data



    2. Relevant equations



    3. The attempt at a solution
     
    Last edited: Mar 30, 2007
  2. jcsd
  3. Mar 30, 2007 #2

    hage567

    User Avatar
    Homework Helper

    You seem to be making the magnification equation more complicated than it needs to be.
     
    Last edited: Mar 30, 2007
  4. Mar 30, 2007 #3
    Isn't magnification M = I/O
    image distance over object distance
     
  5. Mar 30, 2007 #4

    hage567

    User Avatar
    Homework Helper

    No, it's M=-I/O, when I is the image distance, and O is the object distance. You are STILL forgetting the negative sign. If you were taking M in terms of image and object height, then it would be M=I/O, with no negative sign.

    OK, I think I misunderstood what you were doing, but I don't understand why you have the ^-1 exponents in your work. Why can't you take the direct ratio?
     
    Last edited: Mar 30, 2007
  6. Mar 30, 2007 #5
    -0.974 is the image distance over the object distance (which is 12.7)
    So on a graphing calculator, it would be:
    -0.974^-1 divided by 12.7^-1
    and then Ans^-1
    which equals .07669
     
  7. Mar 30, 2007 #6
    Sorry if it was a little confusing the way it was written. I got it correct!
     
  8. Mar 30, 2007 #7

    hage567

    User Avatar
    Homework Helper

    You mean it worked when you put it in the web assign then?
     
  9. Mar 30, 2007 #8
    yes it was correct! :-)Thank you for looking through my work, i always like to make sure when i am down to one chance of getting it right.
     
    Last edited: Mar 30, 2007
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?