# I just need someone to check my work please: glass ornament

1. Mar 30, 2007

### Aikenfan

1. The problem statement, all variables and given/known data

thank you!!!!!

2. Relevant equations

3. The attempt at a solution
1. The problem statement, all variables and given/known data

2. Relevant equations

3. The attempt at a solution

Last edited: Mar 30, 2007
2. Mar 30, 2007

### hage567

You seem to be making the magnification equation more complicated than it needs to be.

Last edited: Mar 30, 2007
3. Mar 30, 2007

### Aikenfan

Isn't magnification M = I/O
image distance over object distance

4. Mar 30, 2007

### hage567

No, it's M=-I/O, when I is the image distance, and O is the object distance. You are STILL forgetting the negative sign. If you were taking M in terms of image and object height, then it would be M=I/O, with no negative sign.

OK, I think I misunderstood what you were doing, but I don't understand why you have the ^-1 exponents in your work. Why can't you take the direct ratio?

Last edited: Mar 30, 2007
5. Mar 30, 2007

### Aikenfan

-0.974 is the image distance over the object distance (which is 12.7)
So on a graphing calculator, it would be:
-0.974^-1 divided by 12.7^-1
and then Ans^-1
which equals .07669

6. Mar 30, 2007

### Aikenfan

Sorry if it was a little confusing the way it was written. I got it correct!

7. Mar 30, 2007

### hage567

You mean it worked when you put it in the web assign then?

8. Mar 30, 2007

### Aikenfan

yes it was correct! :-)Thank you for looking through my work, i always like to make sure when i am down to one chance of getting it right.

Last edited: Mar 30, 2007