Understanding the Relationship between dv/dt and vdv/dx in Calculus

  • Thread starter Brewer
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In summary, the chain rule of differentiation states that the derivative of a composite function is equal to the derivative of the outer function multiplied by the derivative of the inner function. This can be represented algebraically as dv/dt = vdv/dx, where v is the outer function and x is the inner function. The chain rule is often used to find the rate of change of a quantity with respect to another quantity in a more complex function.
  • #1
Brewer
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I have a question that asks me to write dv/dt as a function of x.

I know that dv/dt = vdv/dx

but I don't know why this is. Could anybody shed some light on this for me? Just so I understand why it is this!

Thanks in advance
 
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  • #2
Did you hear about the chain rule of differentiation...?

Daniel.
 
  • #3
dextercioby said:
Did you hear about the chain rule of differentiation...?

Daniel.

yeah that though occurred to me whilst sitting in the car just.

but surely there's another term involved in it isn't there?
 
  • #4
No.

[tex] \frac{dv}{dt}=\frac{dv}{dx}\frac{dx}{dt} [/tex].

Daniel.
 
  • #5
dextercioby said:
No.

[tex] \frac{dv}{dt}=\frac{dv}{dx}\frac{dx}{dt} [/tex].

Daniel.

Of course! What I had in mind was the product rule! Thank you for that - makes so much sense to me now!
 

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