1. The problem statement, all variables and given/known data An ice chest at a beach party contains 12 cans of soda at 3.35 °C. Each can of soda has a mass of 0.35 kg and a specific heat capacity of 3800 J/(kg C°). Someone adds a 9.89-kg watermelon at 26.4 °C to the chest. The specific heat capacity of watermelon is nearly the same as that of water. Ignore the specific heat capacity of the chest and determine the final temperature T of the soda and watermelon in degrees Celsius. Side-note: I believe the the specific heat capacity of water is 4186 J/(kg C°). 2. Relevant equations q=cm∆T 3. The attempt at a solution I'm at a loss at how to attempt this equation. I know the answer is 20°C but I really don't understand how to use the equation to obtain it. My attempt is that heat loss = heat gained but I haven't been able to work it out for myself.