1. The problem statement, all variables and given/known data 2 Identical pellet guns are fired simultaneously from the edge of a cliff. These guns impart an initial speed of 30.0 m/s to each pellet. Gun A is fired straight upward, with the pellet going up the cliff and then falling back down, eventually hitting the ground beneath the cliff. Gun B is fired straight downward. In the absence of air resistance, how long after pellet B hits the ground does pellet A hit the ground. a= 9.8 m/s^2 Vo=30.0 m/s t=? 2. Relevant equations y=Vot + 1/2 at^2 or t=Vo*2/a v=Vo + at 3. The attempt at a solution Here is what I did. 30.0 m/s *2/9.8 m/s^2= 6.12 s. The answer is right, but did I do the problem right.