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C

_{2}H

_{6}+ O

_{2}[itex]\rightarrow[/itex] CO

_{2}+ H

_{2}O

## The Attempt at a Solution

I have tried several times, but the closest I could get was:

2C

_{2}H

_{6}+ 5O

_{2}[itex]\rightarrow[/itex] 2CO

_{2}+ 6H

_{2}O

It is the Oxygen andHydrogen being uneven that is screwing me up. Right away I realize I have 3 Oxygen on the right and 2 on the left, so the first thing I tried to do was make both sides have 6 oxygen...

C

_{2}H

_{6}+ 3O

_{2}[itex]\rightarrow[/itex] CO

_{2}+ 4H

_{2}O

But then that leaves me with 8 Hydrogen on the right, and only 6 on the left...I can't think of any ways to get that 6 to equal 8! Then I tried for 12 Oxygen on both sides instead of 6...then my problem is still Hydrogen.

So maybe y'all see what I'm confused about...like I said, this is the only thing I am having trouble with so far in Gen Chem is balancing this specific type of equation, and we have our first test on Tuesday! So hopefully someone can help :)