1. The problem statement, all variables and given/known data 1. A bottle rocket has an engine that accelerates it upward. Then it coasts to its highest point before returning to the ground. Assuming that the engine creates a net acceleration of 30 m/s2 for 0.5 s, how high does it go, and how long does it take to reach the ground again? acceleration= 30m/s^2 time=0.5s 2. Relevant equations v^2-u^2=2ax 3. The attempt at a solution 0^2-(15m/s)^2=2(-9.8m/s^2)x -225=-19.6x -255/-19.6 x=11.48m to get total height i did 11.48m+3.75m=15.23m now how do i get velocity for the other question v=at v=30m/s^2*0.5s v=15m/s does this work?