- #1

- 6

- 1

## Homework Statement

1. A bottle rocket has an engine that accelerates it upward. Then it coasts to its highest point before returning to the ground. Assuming that the engine creates a net acceleration of 30 m/s2 for 0.5 s, how high does it go, and how long does it take to reach the ground again?

acceleration= 30m/s^2

time=0.5s

## Homework Equations

v^2-u^2=2ax

## The Attempt at a Solution

0^2-(15m/s)^2=2(-9.8m/s^2)x

-225=-19.6x

-255/-19.6

x=11.48m

to get total height i did 11.48m+3.75m=15.23m

now how do i get velocity for the other question

v=at

v=30m/s^2*0.5s

v=15m/s

does this work?