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**1. Homework Statement**

A rocket is launched at an angle that is 53 degrees from the ground. It travels at an initial velocity of 25 m/s, and after a certain point, begins to fly at a constant speed of 25 m/s for 25 seconds. After 25 seconds, the rocket experiences failure and begins to crash toward the ground. What is the horizontal range of the rocket? How far has it traveled?

Givens:

Vi (Initial velocity): 25 m/s

t (Time): 25 seconds

ax (acceleration in the x direction): 0

ay (acceleration in the y direction once the rocket begins to crash): -9.8 m/s

^{2}

Vf (final velocity): ?

horizontal range, or [tex]\Delta[/tex]x: ?

**2. Homework Equations**

Vf = Vi + at

[tex]\Delta[/tex]x or [tex]\Delta[/tex]y = Vi(x,y)t+(1/2)at

^{2}

I'm not too sure if they'll be necessary, but here are some basic trigonometric equations:

cos[tex]\theta[/tex] = adjacent side/hypotenuse

sin[tex]\theta[/tex] = opposite side/hypotenuse

tan[tex]\theta[/tex] = opposite side/adjacent side

**3. The Attempt at a Solution**

I couldn't find a solution, but with the givens I found, I made the following attempts and observations:

If the rocket launched at an initial velocity of 25m/s, reached a constant speed, and then fell from that distance, then it is safe to say that Vf = -25m/s.

Because Vi = 25m/s and Vf = -25m/s, it is safe to say that [tex]\Delta[/tex]y = 0, because 25 + (-25) = 0.

y:

Vi(y) = 25sin53

[tex]\Delta[/tex]y = 0

ay = -9.8m/s

^{2}

t = 25

x:

Vi(x) = 25cos53

[tex]\Delta[/tex]x = ?

ax = 0

t = 25

[tex]\Delta[/tex]x = 25cos53(25) + 0

[tex]\Delta[/tex]x = (25cos53)(25)

Now, the question is: if I finish solving for [tex]\Delta[/tex]x, will I get the answer to the question? Is that the horizontal range?

Can someone please try to help me by the end of the day? My homework is due tomorrow, and if I finish it correctly, I will earn 10 extra points toward my Physics Marking Period Exam (which I need badly)!

**1. Homework Statement**

**2. Homework Equations**

**3. The Attempt at a Solution**