# I need help quick! Integrals

I have a math final tommorow help please!

How do I integrate e^(x^1/3)

Thank you !

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Just to get you started,
Let x^1/3 = t .
dx = 3x^(2/3)dt = 3t^2dt

Can you go from here ?

How did you go from dx = 3x^(2/3)dt to 3t^2dt

Ok I think I get what to do next, substiture dx into the orignal equation?

Last edited:
benorin
Homework Helper
Gold Member
$$dx = 3x^{\frac{2}{3}} dt=3\left( x^{\frac{1}{3}}\right) ^{2} = 3t^2dt$$