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I need help quick! Integrals

  1. Jun 12, 2006 #1
    I have a math final tommorow help please!

    How do I integrate e^(x^1/3)

    Thank you !
     
  2. jcsd
  3. Jun 12, 2006 #2
    Please show your working .

    Just to get you started,
    Let x^1/3 = t .
    dx = 3x^(2/3)dt = 3t^2dt

    Can you go from here ?
     
  4. Jun 12, 2006 #3
    How did you go from dx = 3x^(2/3)dt to 3t^2dt

    Ok I think I get what to do next, substiture dx into the orignal equation?
     
    Last edited: Jun 12, 2006
  5. Jun 12, 2006 #4

    benorin

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    Homework Helper

    [tex]dx = 3x^{\frac{2}{3}} dt=3\left( x^{\frac{1}{3}}\right) ^{2} = 3t^2dt[/tex]
     
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