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I need help with a natural log problem?

  1. Dec 3, 2009 #1
    1. The problem statement, all variables and given/known data
    This is my first time ever posting anything on here.....but we just started working with ln? I know that it's the base e? or something like that...
    but the problem is this....

    1/3=ln(x^2/x-4)


    2. Relevant equations



    3. The attempt at a solution
    I haven't attempted..i don't know how to do it o.o
     
    Last edited: Dec 3, 2009
  2. jcsd
  3. Dec 3, 2009 #2

    ideasrule

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    Homework Helper

    ln is the opposite of "e to the power of", just like how addition is the opposite of subtraction. That is, if you raise e to the power of a certain number, taking the ln of the result gives you back the original number.

    I presume you have to solve for x in 1/3=ln(x^2/x-4). I'll get you started: what happens when you raise e to the power of both sides? That is, e^(1/3)=e^(ln(x^2/x-4)), which simplifies to....
     
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