The suspended 2.2 kg mass on the right is
moving up, the 2 kg mass slides down the
ramp, and the suspended 8.9 kg mass on the
left is moving down. There is friction between
the block and the ramp.
The acceleration of gravity is 9.8 m/s2 . The
pulleys are massless and frictionless.
What is the tension in the cord connected
to the 8.9 kg block?
Answer in units of N.
(Diagram with variables: File posted and also at http://s1219.photobucket.com/albums/dd425/spg93/?action=view¤t=Physics.jpg)
Force of Friction= coefficient of friction*Normal Force
Force of Gravity= mass*gravity
The Attempt at a Solution
I really have no idea where to start. I drew a force diagram for all three boxes. I also solved for the Forces in X direction and forces in Y direction. I figured the forces in the Y direction would be the normal force, so I divided by the coefficient of friction to try and get force of friction. My answer did not work and I'm completely lost. Any help would be really appreciated.
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