- #1
kirsten_2009
- 137
- 2
Homework Statement
Mass of Ferrous Ammonium Sulfate (limiting reagent) = 4.00 grams.
Mass of K3[Fe(C2O4)3].3H2O = 2.54 grams.
QUESTIONS:
1. Using the above mass of ferrous ammonium sulfate calculate the theoretical yield of the K3[Fe(C2O4)3].3H2O
2. What is the percent (%) yield of the K3[Fe(C2O4)3].3H2O
3. Draw the shape of the complex ion {I have this one already...thanks! :)}
4. What is the oxidation state of teh central metal ion?
5. What is the coordination number of the central metal ion?
Homework Equations
(1) FeSO4.(NH4)2SO4.6H2O + H2C2O4.2H2O --> FeC2O4 + (NH4)2SO4 + H2SO4 + 8H2O
(2) 6FeC2O4 + 3H2O2 + 6K2C2O4.H20 --> 4K3[Fe(C2O4)3].3H20 + 2Fe(OH)3
+ 6H20
(3) 2Fe(OH)3 + 3H2C2O4.2H2O + 3K2C2O4.H2O --> 2K3[Fe(C2O4)3].3H2O + 9H2O
The Attempt at a Solution
O.k...I really have NO idea how to do this but here is what I think...
I understand that it's about stoichiometry, recognizing which reactant is the limiting reagent
and then calculating the moles of that reactant and then developing molar ratios. Then, when I have calculated my theoretical yield I could divide my actual yield by it and then multiply by 100 and get my percent yield. The problem is that the equations look long and complex and I'm intimidated. Also, I would have no clue as to the remaining questions. This assignment is worth a lot for me so any help anyone could offer me would be TRULY and GREATLY appreciated, thanks! :)
Last edited: