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I want check my answers

  • Thread starter r-soy
  • Start date
  • #1
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Q : Suppose 9 cards are number with the 9 digits from 1 to 9 . A 3-card hand is dealt, 1 card at a time . How many hands are possible where :

1 ) Order is taken into consideration ?

2 ) order is not taken into considreation ?


----------Ansewr >>


1 - 9C3 X 9C1 = 84 X 9 = 756

2 - 9P3 X 9P1 = 504 X 9 = 4536
 

Answers and Replies

  • #2
vela
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Could you please elaborate on your thinking behind your answers?

You have C and P backwards. Combinations is when you don't care about the order; permutations is when you do. "123" and "321" are the same combination, but they are two possible permutations of 1, 2, and 3.


Q : Suppose 9 cards are number with the 9 digits from 1 to 9 . A 3-card hand is dealt, 1 card at a time . How many hands are possible where :

1 ) Order is taken into consideration ?

2 ) order is not taken into considreation ?


----------Ansewr >>


1 - 9C3 X 9C1 = 84 X 9 = 756

2 - 9P3 X 9P1 = 504 X 9 = 4536
 
  • #3
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Is my answer correct ?
 
  • #4
statdad
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Is my answer correct ?
read vela's post.
 
  • #5
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The ansewr now correct ?

1 - 9P3 X 9P1 = 504 X 9 = 4536

2 - 9C3 X 9C1 = 84 X 9 = 756
 
  • #6
vela
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No, they are not.
 
  • #7
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Help me Give me the answer
 
  • #8
Hurkyl
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No .
 
  • #9
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I tay agine

1 - 9C2 X 9C1 = 36 X 9 = 324

2 - 9P2 X 9P1 = 72 X 9 = 648
 
  • #10
Hurkyl
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Please elaborate on your thinking behind your answers?
 
  • #11
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I can't try more thanks all
 

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