r-soy
Q : Suppose 9 cards are number with the 9 digits from 1 to 9 . A 3-card hand is dealt, 1 card at a time . How many hands are possible where :

1 ) Order is taken into consideration ?

2 ) order is not taken into considreation ?

----------Ansewr >>

1 - 9C3 X 9C1 = 84 X 9 = 756

2 - 9P3 X 9P1 = 504 X 9 = 4536

Staff Emeritus
Homework Helper

You have C and P backwards. Combinations is when you don't care about the order; permutations is when you do. "123" and "321" are the same combination, but they are two possible permutations of 1, 2, and 3.

Q : Suppose 9 cards are number with the 9 digits from 1 to 9 . A 3-card hand is dealt, 1 card at a time . How many hands are possible where :

1 ) Order is taken into consideration ?

2 ) order is not taken into considreation ?

----------Ansewr >>

1 - 9C3 X 9C1 = 84 X 9 = 756

2 - 9P3 X 9P1 = 504 X 9 = 4536

r-soy

Homework Helper

r-soy
The ansewr now correct ?

1 - 9P3 X 9P1 = 504 X 9 = 4536

2 - 9C3 X 9C1 = 84 X 9 = 756

Staff Emeritus
Homework Helper
No, they are not.

r-soy
Help me Give me the answer

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Gold Member
No .

r-soy
I tay agine

1 - 9C2 X 9C1 = 36 X 9 = 324

2 - 9P2 X 9P1 = 72 X 9 = 648

Staff Emeritus