# Ice Calorimetry

Is there anybody that can tell me if I'm doing this question right?

Metallic Ca reacts with hydrochloric acid according to the following equation:
Ca(s) + 2 HCl(aq) ---> 2 CaCl2 (aq) + H2(g)
The enthalpy change associated with this reaction can be determined with an ice calorimeter. If 13.59 g of ice are melted when 0.3487 g of Ca reacts with excess hydrochloric acid, what is deltaH (in kJ/mol Ca) for the reaction written above? The heat of fusion of ice is 333 J/g.

qrxn + qfusion = 0
qrxn = ndeltaHrxn
=(13.59 g H2O)(0.333 kJ/g)
=4.53 kJ

0.3487 g Ca X 1 mol Ca/40.08 g Ca = 8.70 x 10^-3 mol

4.53 KJ/8.70 x 10^-3 mol = 521 kJ/mol?

Does this look right?

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chemisttree
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Looks good to me.

Thanks Chemisttree!!

thack you

plz if anyone who know any thing about ice calorimeter plz go to this subject in chemstry fourm ((i need information about ice calorimeter plz help me.))

thanx much