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Ice cube in the water

  1. Jun 9, 2009 #1
    1. The problem statement, all variables and given/known data

    A cube of ice whose edge measures 20.8 mm is floating in a glass of ice-cold water with one of its faces parallel to the water's surface. How far below the water surface is the bottom face of the block?

    2. Relevant equations

    P=F/A, P2-P1=[tex]\rho[/tex]gh

    3. The attempt at a solution

    so i first found the surface area of the cube which was 2.59584m [using the formula 6*x2]
    then i thought abt equating P1= 101.3 x103Pa. and solve for h but i don't know what to put for P2..pls. help
     
  2. jcsd
  3. Jun 9, 2009 #2

    LowlyPion

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    Aren't you interested in the difference in the density of water and ice? Won't the ratio of the densities work out to be the ratio of the depth below to the whole?
     
  4. Jun 9, 2009 #3
    so if i do the ratio of water to ice so 1000:917 which is about 1.091 is the answer>?
     
  5. Jun 10, 2009 #4
    i'm still unsure on how to do this question pls. help
     
  6. Jun 10, 2009 #5
    nvm i realized my mistake
     
  7. Jun 10, 2009 #6

    LowlyPion

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    Sorry, I missed that it was an open item still.

    Glad you figured it out.
     
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