Ice displacing water question, -need help really bad

1. Jan 16, 2008

ice displacing water question, --need help really bad

1. The problem statement, all variables and given/known data
A rectangular block of ice 6 m on each side and 1.1 m thick floats in seawater. The density of the seawater is 1025 kg/m3. The density of ice is 917 kg/m3.

How high does the top of the ice block float above the water level???

2. Relevant equations

3. The attempt at a solution
1.1 x 917/1025 m = 984 cm (the amount of water displaced).
So, the ice sticks out of the water 1100-984 = 116cm = 1.16m

1. The problem statement, all variables and given/known data

2. Relevant equations

3. The attempt at a solution

2. Jan 16, 2008

hage567

1 m = 100 cm.

You need to use the volume of the ice in your calculation, not just its thickness.

Last edited: Jan 16, 2008
3. Jan 16, 2008

(1.1 x 6 x 6) x 917/1025 m = 35.428cm (the amount of water displaced).
So, the ice sticks out of the water 1100-35.428 = 1064.572cm = 1.064m

still wrong though
????

4. Jan 16, 2008

hage567

Why are you saying this is in cm? The original dimensions were given in meters (at least they were in your original post).
Again, you can't just use the thickness of the ice. How can you subtract a volume from a length? That makes no sense. Draw a diagram, it might help. Once you find the submerged volume, you can find the volume of the ice remaining above the water (since you know the entire volume of the ice). Then you can find the height.

1.1 m DOES NOT equal 1100 cm. Don't bother changing things to cm. Why don't you want to just leave it in meters?

Last edited: Jan 16, 2008