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Ice to water to steam

  1. Nov 28, 2006 #1
    A 55 g ice cube at 0°C is heated until 40 g has become water at 100°C and 15 g has become steam at 100°C. How much energy was added to accomplish the transformation?

    I tried using Q=mL for each change and adding them together.

    Q=.055(3.33x10^5)
    Q=18315

    then

    Q=.015(2.26x10^6)
    Q=33900

    18315+33900= 52215 which is not the correct answer.
     
  2. jcsd
  3. Nov 29, 2006 #2

    OlderDan

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    You have 55g melting (latent heat of fusion) and 55g warming from 0° C to 100° C and then 15g vaporizing (latent heat of vaporization).
     
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