An iceskater weighing 69kg is gliding up an incline hill at 20 degrees.
How high up does the skater make it when her initial velocity is 8,9m/s and the friction between her skates and the ice is 0,97N.
mg(y) = m*g*cos(20)
mg(x) = m*g*sin(20)
The Attempt at a Solution
F(friction) = [itex]\mu[/itex] * mg(y)
F[itex]\rightarrow[/itex] = F(f) + F(mg(x))
a=F[itex]\div[/itex]M[itex]\rightarrow[/itex]F[itex]\div[/itex]m=232,7[itex]\div[/itex]69 = 3,34m/s^2
s = (v^2 - v(o)^2) / 2a = 11,8m
the answer should be 4,0m. What am I doing wrong?