(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

Helium in a steel tank is at 250kPa, 300K with a volume of .1m^3. It is used to fill a balloon. When the pressure drops to 150kPa, the flow of helium stops by itself. If all the helium is still at 300k, how big balloon is produced?

2. Relevant equations

I used the ideal gas law PV=mRT

3. The attempt at a solution

What i did was that i solved for the mass which i got was .04012 and then i used that mass in the ideal gas law with the new pressure of 150kPa to get a new volume of .167 m^3 is this the right approach and answer?

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# Homework Help: Ideal Gas Law and a helium tank

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