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What volume does 1 mole of gas occupy at 1 atm pressure and 273.15K?
PV = nRT so V =nRT/P
V = (1)(8.314)(273.15)/1
Im getting 2270.96, the answer is ment to be 22.4L, what am i doing wrong?
P= 1
V= ?
n= 1
R= 8314
T= 273.15K
PV = nRT so V =nRT/P
V = (1)(8.314)(273.15)/1
Im getting 2270.96, the answer is ment to be 22.4L, what am i doing wrong?
P= 1
V= ?
n= 1
R= 8314
T= 273.15K