IDeal gas law

  • Thread starter Touchme
  • Start date
  • #1
41
0

Homework Statement



An expandable cylinder has its top connected to a spring with force constant 2.00 103 N/m. (See Fig. P10.58.) The cylinder is filled with 6.00 L of gas with the spring relaxed at a pressure of 1.00 atm and a temperature of 20.0°C.


I searched for a similar question however I didnt understand it. Maybe it was the calculation error. Someone help me....

Homework Equations



PV = nRT
[PV/T]i = [PV/T]f
Volume of cylinder = Ah


The Attempt at a Solution



First I convert my units. Initial state: 101325 Pa, 293 K, and 0.006 m^3
I determined the constant by using the gas law PV/T. (101325)(0.006)/293 = 2.0749 [(Nm^2)/K].
After the temperature is increased to 503 K (273+230), the piston rises and the volume changes. The new volume is 0.006 + Ah = 0.006 + 0.01h. The pressure is equal to P = F/A. F is the force constant times dispalcement (h), which is 2000 N/m. P = 2000/0.01 = 200000h N/m^2.
Putting everything together we get
2.0749 = (200000h)(0.006+0.01h)/503

The answer h = 0.482 m or 48.2 cm is incorrect. Any suggestion or corrections. Thank you.
 

Attachments

Last edited:

Answers and Replies

  • #2
Andrew Mason
Science Advisor
Homework Helper
7,610
356

Homework Statement



An expandable cylinder has its top connected to a spring with force constant 2.00 103 N/m. (See Fig. P10.58.) The cylinder is filled with 6.00 L of gas with the spring relaxed at a pressure of 1.00 atm and a temperature of 20.0°C.


I searched for a similar question however I didnt understand it. Maybe it was the calculation error. Someone help me....

Homework Equations



PV = nRT
[PV/T]i = [PV/T]f
Volume of cylinder = Ah


The Attempt at a Solution



First I convert my units. Initial state: 101325 Pa, 293 K, and 0.006 m^3
I determined the constant by using the gas law PV/T. (101325)(0.006)/293 = 2.0749 [(Nm^2)/K].
After the temperature is increased to 503 K (273+230), the piston rises and the volume changes. The new volume is 0.006 + Ah = 0.006 + 0.01h. The pressure is equal to P = F/A. F is the force constant times dispalcement (h), which is 2000 N/m. P = 2000/0.01 = 200000h N/m^2.
Putting everything together we get
2.0749 = (200000h)(0.006+0.01h)/503

The answer h = 0.482 m or 48.2 cm is incorrect. Any suggestion or corrections. Thank you.
You have to develop the equation for pressure:

[tex]P_f = P_i + kh/A = nRT_f/V_f[/tex]

Since [itex]P_i = nRT_i/V_i[/itex], and [itex]V_f = V_i + Ah[/itex]

you should be able to work that out for h.

AM
 

Related Threads on IDeal gas law

  • Last Post
Replies
2
Views
2K
  • Last Post
Replies
3
Views
1K
  • Last Post
Replies
1
Views
788
  • Last Post
Replies
2
Views
4K
  • Last Post
Replies
1
Views
993
  • Last Post
Replies
2
Views
462
  • Last Post
Replies
5
Views
941
  • Last Post
Replies
5
Views
3K
  • Last Post
Replies
2
Views
518
  • Last Post
Replies
9
Views
819
Top