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Ideal gas law

  1. Sep 15, 2008 #1
    (a)
    For a quasistatic adiabatic process involving an ideal gas the temperature and volume are related by: TV^(a-1) = const . By substituting the ideal gas equation into this expression, derive a similar relationship between pressure and volume for an ideal gas in an quasistatic adiabatic process.

    Using PV = nRT and rearranging to get PV/nR=T

    Sub into TV^(a-1) = const --------> (PV/nR)V^(a-1) = const

    (PV^a)/nR = const

    (b)
    In one of the lecture demonstrations it was shown that the temperature of CO2 decreases rapidly as it expands upon release from a fire extinguisher. We could model this process as a quasiadiabatic expansion of an ideal gas to calculate a “ball-park” value for the temperature change of the CO2. If we wanted to use a similar process to cool ammonia, NH3, to its boiling point at 1 atmosphere pressure (a value that you may need to look up) find the initial pressure and temperature that would be required if the volume occupied by the gas increases by a factor of 10 in the expansion process, i.e., final values: pressure p0 = 1 atm, volume = V0 , temperature = boiling point of NH3, initial values: pressure pi = ?, volume Vi = V0/10, temperature Ti = ?. You may need the following information for NH3: Cp/Cv = 1.31.

    Ammonia boiling point = 240k at 1 atm.

    Vi = Vf/10
    Pi =
    Ti =

    Pf = 1atm
    Tf = 240k
    Vf = Vf

    Using the ideal gas law for each then dividing i get Pi/10atm = Ti/240k

    But after this i don't know where to go... i tried using the results from (a) to get Ti or Pi in terms of the other but had no real success.

    Any help or ideas would be greatly appreciated.

    (Cp/Cv = 1.31 <---- what does this actually mean?)

    ----------------------------------------------------------------------------------
    EDIT:

    I realised that Cp/Cv = 1.31 = a

    then solved using the result from part a and got Pi = 20.42 atm and Ti = 490.02k
     
    Last edited: Sep 15, 2008
  2. jcsd
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