Ideal gas law

  • Thread starter ~angel~
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  • #1
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A Jaguar XK8 convertible has an eight-cylinder engine. At the beginning of its compression stroke, one of the cylinders contains 499cm^3 of air at atmospheric pressure (1.01×105 Pa and a temperature of 27.0 C. At the end of the stroke, the air has been compressed to a volume of 46.2 cm^3 and the gauge pressure has increased to 2.72×106 Pa. Compute the final temperature.

I ended up with 69.8 degrees. I used the ideal gas law, but because the mass of air remains constant, i used:

(p1v1/T1) = (p2v2/T2)

I converted the volume to 4.99 x 10^-4 and 4.62 x 10^-5. I also dtermined the final absolute pressure, which is 2.821 x 10^6. But my answer is wrong. Could someone please help.
 

Answers and Replies

  • #2
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It's ok...i forgot to convert to Kelvin.
 
  • #3
dextercioby
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Classical mistake.The weird part is that u converted the volume...:eek:

Daniel.
 
  • #4
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Use the ratios of the volumes, so as dex said you don't need to convert. Also, as you understood, always work with Kelvin!
 
  • #5
dextercioby
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I hope u see that u need the conversion to K in both the initial & final temperature...

Daniel.
 
  • #6
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How did you find the final absolute pressure?
 

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