- #1

- 45

- 0

[tex]\int_{V_i}^{V_f} P dV [/tex]

But what if [tex]V_f \prec V_i [/tex]? If [tex]W \prec 0[/tex] does that mean

1) work is done

**on**the gas or

2)on this case, [tex]W= - \int_{V_i}^{V_f} P dV [/tex] so that [tex]W \succ 0[/tex] and W still means the work done by the gas?

Note: The question may seem obvious but the derivation of the above expression only makes sense for work done by the gas