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## Homework Statement

pV=nRT dV=10cm^3/min dP=-0,3N/cm^2/min n=5mol V=100cm^3 P=2N/cm^2 where d is change.

how does tempperature(T) change( dT/t ) compared to time

## The Attempt at a Solution

No idea

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- Thread starter Cadmatic
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- #1

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pV=nRT dV=10cm^3/min dP=-0,3N/cm^2/min n=5mol V=100cm^3 P=2N/cm^2 where d is change.

how does tempperature(T) change( dT/t ) compared to time

No idea

- #2

rock.freak667

Homework Helper

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d(PV)=d(nRT)

(use the product law on the left side)

I'll help you with the right side :)

d(nRT)=nR(dT)

- #3

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So PdV+dPV=nRdT

dT=PdV+dPV/nR

dT=2*10-0.3*100/5R

dT=-10/5R ... ?

dT=PdV+dPV/nR

dT=2*10-0.3*100/5R

dT=-10/5R ... ?

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