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Ideal gas

  1. Oct 19, 2009 #1
    1. The problem statement, all variables and given/known data

    pV=nRT dV=10cm^3/min dP=-0,3N/cm^2/min n=5mol V=100cm^3 P=2N/cm^2 where d is change.
    how does tempperature(T) change( dT/t ) compared to time


    3. The attempt at a solution

    No idea
     
  2. jcsd
  3. Oct 19, 2009 #2

    rock.freak667

    User Avatar
    Homework Helper

    Consider expanding

    d(PV)=d(nRT)

    (use the product law on the left side)


    I'll help you with the right side :)

    d(nRT)=nR(dT)
     
  4. Oct 20, 2009 #3
    So PdV+dPV=nRdT

    dT=PdV+dPV/nR

    dT=2*10-0.3*100/5R

    dT=-10/5R ... ?
     
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