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hils0005
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[SOLVED] Ideal gases
an air bubble of volume 20cm^3 is at the bottom of a lake 40m deep where the temp is
4C, the bubble rises to the surface which is at temp 20C, take the temp of the buble to match that of the surrounding water, just as the bubble reaches the surface, what is it's volume?
pV=nRT
p(f)V(f)/p(i)V(i)=nRT(f)/nRT(i)
final pressure= 1.01*10^5Pa
V(i)=20x10^-6m^3
T(i)=277K
T(f)=293K
would need to determine the pressure on the bubble at the bottom of the lake, which I can't remember how to determine
p=hp(density)g?
p=40m(1000kg/m^3)9.8m/s^2
p=39.2x10^4
Vf=(T(f)*(p(i)V(i))/(T(i)p(f))
Vf=(293 * 39.2x10^4 * .00002)/(277*101000)
Vf=2297.12/2.7977x10^7=8.2x10^-5m^3
This shows the volume decreased, wouldn't the volume increase?
an air bubble of volume 20cm^3 is at the bottom of a lake 40m deep where the temp is
4C, the bubble rises to the surface which is at temp 20C, take the temp of the buble to match that of the surrounding water, just as the bubble reaches the surface, what is it's volume?
Homework Equations
pV=nRT
p(f)V(f)/p(i)V(i)=nRT(f)/nRT(i)
final pressure= 1.01*10^5Pa
V(i)=20x10^-6m^3
T(i)=277K
T(f)=293K
The Attempt at a Solution
would need to determine the pressure on the bubble at the bottom of the lake, which I can't remember how to determine
p=hp(density)g?
p=40m(1000kg/m^3)9.8m/s^2
p=39.2x10^4
Vf=(T(f)*(p(i)V(i))/(T(i)p(f))
Vf=(293 * 39.2x10^4 * .00002)/(277*101000)
Vf=2297.12/2.7977x10^7=8.2x10^-5m^3
This shows the volume decreased, wouldn't the volume increase?
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