- #1

Tanya Sharma

- 1,540

- 135

## Homework Statement

Two closed containers A and B contain equal number of moles of ideal gases G

_{D}(diatomic)and G

_{M}(Monoatomic) ,respectively.

Q .1 a) If the temperature of gases are same,which of them has more average translational kinetic energy ?

b) Which of them has more internal energy ?

Q.2 a) If the temperature of G

_{M}( T

_{M})is greater than G

_{D}(T

_{D}) ,which of them has more average translational kinetic energy ?

b) Which of them has more internal energy?

## Homework Equations

Average translational kinetic energy of n moles of ideal gas= (3/2)nRT

Internal energy of n moles of ideal gas =(f/2)nRT ,f is the degree of freedom.

## The Attempt at a Solution

1.a) Since the temperature is equal,average translational kinetic energy of both the gases is same .

1.b) The internal energy of G

_{D}is (5/2)nRT is greater than internal energy of G

_{M},which is (3/2)nRT

2.a) Since T

_{D}< T

_{M},the average translational kinetic energy of G

_{D}is less than that of G

_{D}.

2.b) When T

_{D}< (3/5)T

_{M},internal energy of G

_{D}is less than that of G

_{M}.But when (3/5)T

_{M}<T

_{D}<T

_{M},the internal energy of G

_{D}is more than that of G

_{M}.

I would deeply appreciate if someone could check my work along with the reasoning .