http://img38.imageshack.us/img38/6127/88280233.jpg [Broken] I circled the given answer. The problem asks for I and V. I guess the bottom diode shorts first and then that makes the top two diodes be open circuited. Is there any good explanation on why the circuit behaves like that? I guess it comes from the fact that three different voltages relative to ground cannot be applied to the same node? Therefore, the diode with the lowest voltage on its anode "wins" and the other diodes shut off due to the negative [tex]V_D[/tex]?