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Ideal Quantum Experiment

  1. Jun 23, 2007 #1
    In the discussion of the ideal quantum experiment and Compton scattering, my book (Shankar page 23) gives these equations for the conservation of momentum and energy:

    [tex] cp' = cp +h-bar(\omega+\omega') [/tex]
    [tex] E' = E +h-bar(\omega-\omega') [/tex]

    This experiment involved a photon of known energy and momentum colliding with a particle of unknown energy and momentum.

    c is the speed of light, h-bar is h/(2*pi) omega is the frequency of the photon, E is energy, and p is momentum

    Can someone please explain how those equations represent the conservation of momentum and energy?
    Last edited: Jun 23, 2007
  2. jcsd
  3. Jun 23, 2007 #2
    Put glasses on your nose if you need: this is what is written.

    Regards, Dany.
  4. Jun 23, 2007 #3
    Why is it [tex] \omega - \omega'[/tex] for energy and [tex] \omega + \omega'[/tex] for momentum?
  5. Jun 24, 2007 #4
    I see the photon is moving at first and right-moving after the collision and p and p' are only the modulus of the momentum.
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