Ideal Springs

  • Thread starter dcgirl16
  • Start date
  • #1
27
0
I have this question
THe work done to compress a spring with a force constant of 290.0 N/m a total of 12.3mm is.. and the answer is .0219J but i cant get this answer
This is what i did
F=kx
F=290(.0123)
F=3.567

W=Fcos0 d
W=3.567(.0123)
.0439J

What am i doing wrong??
 

Answers and Replies

  • #2
Office_Shredder
Staff Emeritus
Science Advisor
Gold Member
3,999
218
Notice the force is different for different distances, thus, Fd doesn't really work here.

Do you know what the potential energy is for a spring with spring constant k compressed a distance of x?
 
  • #3
27
0
do you mean the elastic potential Ee=1/2kx2
and then would i use that in the work equation?
 
  • #4
Office_Shredder
Staff Emeritus
Science Advisor
Gold Member
3,999
218
It's conservation of energy. Work must have been done against the spring to give the spring that potential energy.
 

Related Threads on Ideal Springs

  • Last Post
Replies
2
Views
2K
  • Last Post
Replies
3
Views
1K
  • Last Post
Replies
4
Views
3K
  • Last Post
Replies
2
Views
9K
  • Last Post
Replies
3
Views
526
  • Last Post
Replies
3
Views
8K
  • Last Post
Replies
1
Views
2K
Replies
1
Views
19K
  • Last Post
Replies
3
Views
2K
  • Last Post
Replies
1
Views
970
Top