First of all I've read the sticky and I am not trying to get somebody to do my homework. I have been working on this problem for the last two weeks and have the piles of paper to prove it. Here is my problem: Two identical 7.5u-c charges start from rest and are initially spaced 5.5 cm from each other. If we fix the one charge, and let the other go free, how fast will it be moving when the charges are 30 cm apart? Assume the charges have mass 10^-6 kg. The solution is 3877 m/s.(adsbygoogle = window.adsbygoogle || []).push({});

Roads I've been down:

v^2= vay^2 + 2ay(y-y0)

= 0 + 2ay(24.5)

v= sqrt(2a(24.5))

= 2632 m/s

mv^2= KQ^2/r

v^2 = KQ^2/rm

v=sqrt((9*10^9)(7.5 X 10^-6)^2)/(0.055m)(1*10^-6))

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# Homework Help: Identical Charges

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