# Identify Acid using Stoic

1. Nov 16, 2017

### Lori

1. The problem statement, all variables and given/known data
8.040 grams of a strong, monoprotic acid was added to enough water to make 500 ml of solution and used o completely neutralize 2.080 g aluminum hydroixide. identify the acid.

2. Relevant equations

m1v1 = m2v2
M = n/1 Liter
3. The attempt at a solution

i know that 2.08 g of Aluminum hydroxide is 0.02667 mols using molar mass of Aluminum hydroxide.
I also might know that there is 491.96 grams of water since i took the % from 8.040 grams/500 ml. Not sure if this is correct. I'm kinda stuck from here on.

I somewhat got a chemical equation going on with HX + Al(OH)3 --> H2O + AlX

2. Nov 16, 2017

### mjc123

What do you think would be the stoichiometry of the HX - Al(OH)3 reaction?

3. Nov 16, 2017

### Lori

You mean the mole conversions? I think X would have 3 mols right because Al has a +3 charge

4. Nov 16, 2017

### Staff: Mentor

See my comment in your second titration thread. Forget you ever saw this formula.

5. Nov 16, 2017

### Lori

I'm aware that this formula won't work with this problem but I'm still stuck

6. Nov 16, 2017

### Staff: Mentor

Balance the reaction correctly and use the masses given to calculate molar mass of HX.

7. Nov 16, 2017

### Lori

Ok. I got 100 grams/lol of HX using 3 moles HX/1mol al (oh)2

So Since it says strong acid, I just have to match it to the molar mass of the list of strong acids I know right? It would be HCLO4 since it also as like 100g/mol

8. Nov 16, 2017

### Staff: Mentor

Looks reasonable.