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Homework Help: Identify Acid using Stoic

  1. Nov 16, 2017 #1
    1. The problem statement, all variables and given/known data
    8.040 grams of a strong, monoprotic acid was added to enough water to make 500 ml of solution and used o completely neutralize 2.080 g aluminum hydroixide. identify the acid.

    2. Relevant equations

    m1v1 = m2v2
    M = n/1 Liter
    3. The attempt at a solution

    i know that 2.08 g of Aluminum hydroxide is 0.02667 mols using molar mass of Aluminum hydroxide.
    I also might know that there is 491.96 grams of water since i took the % from 8.040 grams/500 ml. Not sure if this is correct. I'm kinda stuck from here on.

    I somewhat got a chemical equation going on with HX + Al(OH)3 --> H2O + AlX
     
  2. jcsd
  3. Nov 16, 2017 #2

    mjc123

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    Science Advisor

    What do you think would be the stoichiometry of the HX - Al(OH)3 reaction?
     
  4. Nov 16, 2017 #3
    You mean the mole conversions? I think X would have 3 mols right because Al has a +3 charge
     
  5. Nov 16, 2017 #4

    Borek

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    Staff: Mentor

    See my comment in your second titration thread. Forget you ever saw this formula.
     
  6. Nov 16, 2017 #5
    I'm aware that this formula won't work with this problem but I'm still stuck
     
  7. Nov 16, 2017 #6

    Borek

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    Staff: Mentor

    Balance the reaction correctly and use the masses given to calculate molar mass of HX.
     
  8. Nov 16, 2017 #7
    Ok. I got 100 grams/lol of HX using 3 moles HX/1mol al (oh)2

    So Since it says strong acid, I just have to match it to the molar mass of the list of strong acids I know right? It would be HCLO4 since it also as like 100g/mol
     
  9. Nov 16, 2017 #8

    Borek

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    Staff: Mentor

    Looks reasonable.
     
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