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Identify Acid using Stoic

  • Thread starter Lori
  • Start date
  • #1
Lori

Homework Statement


8.040 grams of a strong, monoprotic acid was added to enough water to make 500 ml of solution and used o completely neutralize 2.080 g aluminum hydroixide. identify the acid.

Homework Equations



m1v1 = m2v2
M = n/1 Liter

The Attempt at a Solution



i know that 2.08 g of Aluminum hydroxide is 0.02667 mols using molar mass of Aluminum hydroxide.
I also might know that there is 491.96 grams of water since i took the % from 8.040 grams/500 ml. Not sure if this is correct. I'm kinda stuck from here on.

I somewhat got a chemical equation going on with HX + Al(OH)3 --> H2O + AlX
 

Answers and Replies

  • #2
mjc123
Science Advisor
Homework Helper
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What do you think would be the stoichiometry of the HX - Al(OH)3 reaction?
 
  • #3
Lori
You mean the mole conversions? I think X would have 3 mols right because Al has a +3 charge
 
  • #4
Borek
Mentor
28,328
2,717
m1v1 = m2v2
See my comment in your second titration thread. Forget you ever saw this formula.
 
  • #5
Lori
See my comment in your second titration thread. Forget you ever saw this formula.
I'm aware that this formula won't work with this problem but I'm still stuck
 
  • #6
Borek
Mentor
28,328
2,717
Balance the reaction correctly and use the masses given to calculate molar mass of HX.
 
  • #7
Lori
Ok. I got 100 grams/lol of HX using 3 moles HX/1mol al (oh)2

So Since it says strong acid, I just have to match it to the molar mass of the list of strong acids I know right? It would be HCLO4 since it also as like 100g/mol
 
  • #8
Borek
Mentor
28,328
2,717
Looks reasonable.
 

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