If light travels for 3.0ns in ethyl alcohol, how much furthe

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Homework Help Overview

The discussion revolves around the speed of light in different media, specifically ethyl alcohol and benzene, and how far light travels in these substances over a time interval of 3.0 nanoseconds. The problem involves concepts of refractive index and distance calculation based on speed and time.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the ratio of the speed of light in ethyl alcohol to that in benzene, questioning the calculations and interpretations of distance traveled in each medium over a specified time.

Discussion Status

Participants are actively engaging with the problem, raising questions about the definitions and calculations involved. Some guidance has been offered regarding the interpretation of the refractive index and the need to clarify units in calculations. There is an ongoing exploration of how to visualize and compute the distances traveled by light in both substances.

Contextual Notes

There is a noted uncertainty regarding the application of the refractive index and the calculations of distance, with participants expressing confusion about the correct approach to the problem.

tangowhiskey
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Ratio is 1.10 for part 1.
1. Determine the ratio for the speed of light in ethyl alcohol (n=1.36) to the speed of light in benzene (n=1.50).

2. If light travels for 3.0ns in ethyl alcohol, how much further will it travel in this material than it would in benzene? answer will be in terms of speed of light in benzene, Vbenzene.

here is my work for part 2 but i don't think its right,

for part 2 knowing Ve/Vb = 1.10

d=Vet

Vc=(1.10)Vb
d=Vet
Ve=(1.10)Vb
de=(1.1)Vbt
de=(3.0x10^9s)Vb

d=1.10Vb x 3.0x10^-3

d=1.10 x 3x10^-3 Vb

Vb(3x10^-9) = d
 
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tangowhiskey said:
Ratio is 1.10 for part 1.
1. Determine the ratio for the speed of light in ethyl alcohol (n=1.36) to the speed of light in benzene (n=1.50).

2. If light travels for 3.0ns in ethyl alcohol, how much further will it travel in this material than it would in benzene? answer will be in terms of speed of light in benzene, Vbenzene.

here is my work for part 2 but i don't think its right,

for part 2 knowing Ve/Vb = 1.10

d=Vet

Vc=(1.10)Vb
d=Vet
Ve=(1.10)Vb
de=(1.1)Vbt
de=(3.0x10^9s)Vb

d=1.10Vb x 3.0x10^-3

d=1.10 x 3x10^-3 Vb

Vb(3x10^-9) = d
Your final result doesn't make any sense. All you've done is multiply Vb by 3 ns. The question asks how much further does light travel in ethyl alcohol in 3 ns than it does in the same time in benzene.

What's the definition of the index of refraction n of a material, in terms of the speed of light c?

https://en.wikipedia.org/wiki/Refractive_index
 
SteamKing said:
Your final result doesn't make any sense. All you've done is multiply Vb by 3 ns. The question asks how much further does light travel in ethyl alcohol in 3 ns than it does in the same time in benzene.

What's the definition of the index of refraction n of a material, in terms of the speed of light c?

https://en.wikipedia.org/wiki/Refractive_index
correct me if I am wrong but it might be

speed of light in benzene (3x10^8)/(1.50) = 2x10^8 m/s

now I am unclear about what to do..
 
tangowhiskey said:
correct me if I am wrong but it might be

speed of light in benzene (3x10^8)/(1.50) = 2x10^8 m/s

now I am unclear about what to do..
Well, you know (I hope) that distance traveled = speed × time.

In step 1, you calculated the ratio of the indices of refraction for ethyl alcohol to benzene and found that ratio to be about 1.10. This is how much faster light travels thru ethyl alcohol than benzene. Over 3 ns, how much farther does light travel thru ethyl alcohol than benzene? "How much farther" means what's the difference in distance traveled in the two liquids during the same amount of time.
 
SteamKing said:
Well, you know (I hope) that distance traveled = speed × time.

In step 1, you calculated the ratio of the indices of refraction for ethyl alcohol to benzene and found that ratio to be about 1.10. This is how much faster light travels thru ethyl alcohol than benzene. Over 3 ns, how much farther does light travel thru ethyl alcohol than benzene? "How much farther" means what's the difference in distance traveled in the two liquids during the same amount of time.

so then

d = (1.10)(3x10^-9) = 3.3 x 10^-9 seconds

??
 
tangowhiskey said:
so then

d = (1.10)(3x10^-9) = 3.3 x 10^-9

??
No, you're not even writing out the units with your calculations, which you should always do. Remember, 1.10 is a ratio; it is unitless. If you multiply a ratio by a velocity, you're going to get another velocity, not a distance.

In this case, perhaps making a simple sketch would help you visualize what's happening.

Pretend you have two containers, one filled with ethyl alcohol and the other filled with benzene. How would you show the distance light travels thru each container in 3 ns? How would you show the difference in the distance light traveled in each fluid?
 
SteamKing said:
No, you're not even writing out the units with your calculations, which you should always do. Remember, 1.10 is a ratio; it is unitless. If you multiply a ratio by a velocity, you're going to get another velocity, not a distance.

In this case, perhaps making a simple sketch would help you visualize what's happening.

Pretend you have two containers, one filled with ethyl alcohol and the other filled with benzene. How would you show the distance light travels thru each container in 3 ns? How would you show the difference in the distance light traveled in each fluid?

my physics is too poor to figure this out
 

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